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Question 14 — Akses Array Berantai

Analisis Kode · 20 points · Answer key: 6

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#include <iostream>
using namespace std;
int main() {
    int a[10] = {7, 4, 5, 0, 2, 3, 8, 1, 9, 6};
    int sum = 0;
    for (int i = 0; i < 10; i++) {
        sum += a[i];
    }
    a[7] = a[a[a[a[a[a[a[7]]]]]]];
    int sum2 = 0;
    for (int i = 0; i < 10; i++) {
        sum2 += a[i];
    }
    cout << sum2 - sum << endl;
    return 0;
}

Jawab: …………………………………………………… {tuliskan output program}

Answers (7 members)